Question

1.A student determined the calorimeter constant of the calorimeter, using the procedure described in this module. The student added 50.00 mL of cold water to 50.00 mL of heated, distilled water in a Styrofoam cup. The initial temperature of the cold water was 19.09°C and of the hot water, 32.17°C. The maximum temperature of the mixture was found to be 24.55°C. Assume the density of water is 1

Answer 1

coldwater mass of cold water and density & volume = 19/me* 50.00mL = 50.000 Initial temperature (T) = 19.09e - Equilibrium temperature CT2) = 24.53 Hotwater specific heat of water (si)= 4-184 I/9°C mass of hot water (mg) = 19/mLx50.00 mL zSooog B Initial Temp @TB) = 32017 1 tinal tempo 24.55°c - Q Hot water so specificheat capacity (S₂)=4-184562 =+6 cold water t lealtat ) O q=ms at - 50gx4.184 lgic (24.55 -32.17) = 509x4-184 5/6 (24.53-190 1599 1 142.232 + Ccal (5.460) Calorimeter constant ceal) = 827657°c