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can you find this answer at 350K? I know how to find it at standard conditions! Thanks!
7. Calculate the Gibbs energy change from the standard cell potential following redox reactions at 350 K. AG = -nfeo Ag+ (aq)
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Answer #1

E0(cell) = E0 (Ag+ / Ag) - E0(Mg^2+ / Mg)

or

E0(cell) = 0.80 + 2.37 = 3.17 V

Mg.................> Mg^2+ + 2e

thus

n = 2

and

we know,

delta G = - nF * E0(cell) = - 2 * 96485 * 3.17 = - 611715 J / mole = - 611.7 KJ / mole (answer)

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