Please can I get step solution to question. Answer is provided.
K2CrO4 + 2Ag + 2FeCl3 à Ag2CrO4 + 2FeCl2 +2KCl
2Ag + CrO42- → Ag2CrO4 + 2e-
2FeCl3 + 2e- → 2FeCl2 + 2Cl-
delta G = -nFEcell
-62.5 x 103 J/mol= -(2 mol) (96500 c/mol) Ecell
Ecell = 62.5/(2 x 96.5) = 0.324 V
Ecell = Ecello – RT/nF lnq
0.324 = RT/nF ln [Red/Oxid]
0.324 = SPEFe -SPEAg
Fe+3/Fe2+ = 0.77
SPEAg = 0.77-0.324 = 0.45V
Please can I get step solution to question. Answer is provided. 2 The standard reaction Gibbs...
The standard Gibbs energies of formation for Cu2+ (aq) and Fe3+ (aq) are 65.49 kJ mol-1 and -4.7 kJ mol-1 respectively. What is the standard potential (Volts) at 298 K for the cell: 3Cu2+(aq) + 2Fe(s) + 2Fe3+ (aq) + 3Cu(s)
Calculate the standard change in Gibbs free energy, AG , for the given reaction at 25.0 "C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH, CI() = NH(aq) + Cl" (aq) AGxn = kJ/mol Determine the concentration of NH(aq) if the change in Gibbs free energy, AGx. for the reaction is -9.39 kJ/mol. INH1 = Thermodynamic Properties at 298 K So 0 1 ΔΗ kJ/mol 0 105.8 -31.1 -32.6 -100.4 -127.0 -61.8 -124.4...
can
I get help with ALL THREE of these questions, please?
A reaction has a standard free-energy change of -17.30 kJ mol-'(-4.135 kcal mol-'). Calculate the equilibrium constant for the reaction at 25°C. Kog What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 14.81 kJ/mol K= For a particular reaction at 189.0 °C, AG = -424.14 kJ, and AS = 149.31 J/K. Calculate AG for this reaction at -101.8 °C. AG =...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
Please show all work step by step and final
answer.
Reference Electrodes The Eº value for the following reaction is 0.446 V relative to the standard hydrogen electrode (SHE): Ag2 CrO4(s) + 24 + 2Ag(s) + Cro42 (aq) A chemist wishes to determine the concentration of Cro42- electrochemically. A cell is constructed consisting of a saturated calomel electrode (SCE; which has a reduction potential of 0.242 V relative to the SHE) and a silver wire coated with Ag Cro4 and...
Calculate the standard change in Gibbs free energy, AGixn , for the given reaction at 25.0 °C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH,CI() = NH(aq) + Cl(aq) AGxn = -7.7 kJ/mol Determine the concentration of NH(aq) if the change in Gibbs free energy, AGrxn , for the reaction is –9.53 kJ/mol. [NH] = 0.72 Consider a general reaction enzyme A(aq) = B(aq) The AG® of the reaction is -4.880 kJ mol-....
Calculate the standard molar Gibbs energy of a solution that has a
chemical potential of 5.9 kj/mol at 222K and 12 bar.
6. Calculate the standard molar Gibbs energy of a solution that has a chemical potential of 5.9 kJ/mol at 222 K and 12 bar.
Calculate the standard change in Gibbs free energy, Δ?∘rxnΔGrxn∘ , for the given reaction at 25.0 ∘C25.0 ∘C . Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. KCl(s)↽−−⇀K+(aq)+Cl−(aq)KCl(s)↽−−⇀K+(aq)+Cl−(aq) Δ?∘rxn= Determine the concentration of K+(aq)K+(aq) if the change in Gibbs free energy, Δ?rxnΔGrxn , for the reaction is −8.31 kJ/mol−8.31 kJ/mol . [K+]=
i need the K+ value this question was submitted already but
the second answer i got was incorrect.
Calculate the standard change in Gibbs free energy, AGn, for the following reaction at 25.0 °C. Standard Gibbs free energy of formation values can be found here. rxn: KCI K (aq)+ CI (ag) Number kJ/ mol Then, determine the concentration of K*(aq) if the change in Gibbs free energy, AGn, for the reaction is -8.45 kJ/mol. Number M
Calculate the standard change...
can you find this answer at 350K? I know how to find it at
standard conditions! Thanks!
7. Calculate the Gibbs energy change from the standard cell potential following redox reactions at 350 K. AG = -nfeo Ag+ (aq) + Mg(s) S Ag(s) + Mg(aq) (a)