If a person received a test score that is in the top 32% of all test...
If a person received a test score that is in the top 32% of all test scores, the person’s z-score must be at least 0.46. How did we come up with 0.46? What is the formula used?
Homework Answers
Solution:-
Given that
Using standard normal table,
P(Z > z) = 32%
= 1 - P(Z < z) = 0.32
= P(Z < z) = 1 - 0.32
= P(Z < z ) = 0.68
= P(Z < 0.46 ) = 0.68
z = 0.46
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