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70 Homework:Section 8.1 Homework Save Score: 0.17 of 1 pt 10 of 13 (13 complete) HW Score: 51.44 % , 6.69 of 13 pts 8.1.27-T
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Answer #1

Solution:

Given: Population mean = u= 5
Population Standard Deviation = 0 = V5 = 2.236068
Sample size = n = 50
We have to find mean and standard deviation of sample distribution of sample mean \bar{x} .

Since sample size n = 50 is large , we can use Central limit theorem which states that for large sample size n ,
sampling distribution of sample mean is approximately normal with mean of sample means:

Vi=

Me=5

and standard deviation of sample means is:

0i = n

oi= 2.236068 V50

0 = 2.236068 7.071068

0 = 0.316228

0= 0.316

( Round answer to specified number of decimal places)

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