Question
Find D.
A political pollster is conducting an analysis of sample results in order to make predictions on election night. Assuming a two-candidate election, if a specific candidate receives at least 55% of the vote in the sample, that candidate will be forecast as te winner of he election. You select a random sample of 100 votes. Complete parts (a) through (c) below Home ork The probability is .1151 that a candidate wil be forecast as the winner when the population percentage of her vote is 49% & Tes Round to four decimal places as noeded.) d. Suppose that the sample size was increased to 400. Repeat process (a) through (c), using this new sample size. Comment on the difference. en The probability is .0250 that a candidate wil be forecast as the winner when the populason percentage of her vote is 50.1% (Round to four decimal places as needed.) ook The probability is that a candidate wil be forecast as the winner when the population percentage of her vote is 58% r Cont (Round to four decimal places as needed.) or Suce Enter your answer in the answer box and then click Check Answer nedia L remaining Clear All Check Answer eTools
0 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1

d) Calculate the probability that the candidate wil be forecast as the winner when the population percentage of her vote is 50.1% p-p p(1-p 72 , 0.55-p p(1-p P(B2055)-1- 72 0.55-0.501 0.501(1-0.501) 400 1-P(Z<1.96) 1-0. 9750 0.0250 The probability is 0.0250 that a candidate will be forecast as the winner when the population percentage of her vote is 50.1% Calculate the probability that the candidate wil be forecast as the winner when the population percentage of her vote is 58%P(p2058) = 1-P- p-p p(1-p p(1-p 72 72 1-P Z <-0.55-0.58 0.58(1-0.58) 400) = 1-P(Z <-1.22) -1-0.1121 -0.8879 The probability is 0.8879 that a candidate will be forecast as the winner when the population percentage of her vote is 58%

Add a comment
Know the answer?
Add Answer to:
Find D. A political pollster is conducting an analysis of sample results in order to make...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • A political pollster is conducting an analysis of sample results in order to make predictions on...

    A political pollster is conducting an analysis of sample results in order to make predictions on election night. Assuming a​ two-candidate election, if a specific candidate receives at least 53% of the vote in the​ sample, that candidate will be forecast as the winner of the election. You select a random sample of 100 voters. a. What is the probability that a candidate will be forecast as the winner when the population percentage of her vote is 50.1​%? The probability...

  • In a randomly selected sample of 500 registered voters in a community, 260 individuals say that...

    In a randomly selected sample of 500 registered voters in a community, 260 individuals say that they plan to vote for Candidate Y in the upcoming election. (a) Find the sample proportion planning to vote for Candidate Y. (Round your answer to two decimal places.) (b) Calculate the standard error of the sample proportion. (Round your answer to three decimal places.) (c) Find a 95% confidence interval for the proportion of the registered voter population who plan to vote for...

  • In a randomly selected sample of 500 registered voters in a community, 320 individuals say that...

    In a randomly selected sample of 500 registered voters in a community, 320 individuals say that they plan to vote for Candidate Y in the upcoming election. (a) Find the sample proportion planning to vote for Candidate Y. (Round your answer to two decimal places.) (b) Calculate the standard error of the sample proportion. (Round your answer to three decimal places.) (c) Find a 95% confidence interval for the proportion of the registered voter population who plan to vote for...

  • A popular news agency covering a local election will declare a winner when their sample data...

    A popular news agency covering a local election will declare a winner when their sample data provides enough evidence that the proportion of all voters who will vote for that candidate is a majority—more than 50%. If data from a random sample of 120 voters indicates that 66 of them are voting for a certain candidate, what value of z is the test statistic? (Round your answer to two decimal places.)

  • In a certain presidential election, Alaska's 40 election districts averaged 1,958.8 votes per district for a...

    In a certain presidential election, Alaska's 40 election districts averaged 1,958.8 votes per district for a candidate. The standard deviation was 572.5. (There are only 40 election districts in Alaska.) The distribution of the votes per district for one candidate was bell-shaped. Let X = number of votes for this candidate for an election district Parta State the approximate distribution of X. (Enter your numerical values to one decimal place) X-NO Parth Is 1,9588 a population mean or a sample...

  • If, based on a sample size of 950, a political candidate finds that 514 people would...

    If, based on a sample size of 950, a political candidate finds that 514 people would vote for him in a two-person race, what is the 90% confidence interval for his expected proportion of the vote? Would he be confident of winning based on this poll? | || A 90% confidence interval for his expected proportion of the vote is || (Use ascending order. Round to four decimal places as needed.)

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 384 with 87% successes at a confidence level of 99.5%. M.E. = % Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place A political candidate has asked you to conduct a poll to determine what percentage of people...

  • a. Assume that a sample is used to estimate a population proportion p. Find the 95%...

    a. Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 198 with 42 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 95% C.I. = b. A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 0.5% margin of error at a 99% confidence...

  • Suppose a simple random sample of size n=200 is obtained from a population whose size is...

    Suppose a simple random sample of size n=200 is obtained from a population whose size is N = 30,000 and whose population proportion with a specified Charadelei isp.06. Complete purt (a) through k) below O C. Not normal because no.05N and np(1-P) 10 OD. Approximately normal because 0.05N and np{1 - p)<10 P Determine the mean of the sampling distribution of 06 (Round to one decimal place as noeded) Determine the standard deviation of the sampling distribution of 0.0.034541 (Round...

  • Name: MAT 152-Central Theorem Project Round all answers to four decimal places unless directed otherwise. SHOW...

    Name: MAT 152-Central Theorem Project Round all answers to four decimal places unless directed otherwise. SHOW WORK Scotland County has a population of 35,093 people. Of those, 22,429 people are registered to vote. 1. What proportion of Scotland County citizens are registered to vote? 2. If 50 people are randomly selected, what is the probability that at least 75 % of them are registered to vote? 3. If 100 people are randomly selected, what is the probability that at least...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT