Question

3. a) Draw both chair conformations for the molecule shown below. (2pts) b) Circle the most stable conformation above. Give a brief explanation on why your choice is more stable. (2pts)

b) Circle the most stable conformation above. Give a brief explanation on why your choice is more stable. (2pts)

3. a) Draw both chair conformations for the molecule shown below. (2pts) HO OH b) Circle the most stable conformation above. Give a brief explanation on why your choice is more stable. (2pts)

Answer 1

Ans a & b но Он 1 (R) Here 'OH at position 1 & 3 are cis/syn to each other (1R 3S)-cyclohexane-1,3-diol Chair form of (R3S)-cyclohexane-1,3-diol (В) (A) H OH 6 Он Flipping 6 но 3 2 1 1. Both 'OH' groups are in axial position 1. Both 'OH' groups are in equatorial position 2. There exists intramolecular 2. No intramolecular hydrogen bonding Hydrogen bonding between 'OH groups 3. More stable 3. Less stable =Chair conformer (A) is more stable than chair conformer (B). Because conformer (A) can allow the formation of intramolecular hydrogen bonding which stabilizes the molecule (see above diagram) Formation of intramolecular hydrogen bonding is not possible with conformer (B).(see above diagram)