To find the proportion between the mean that is z = 0 and z = 0.52, use z distribution table
The table gives the left side area to the z
Proportion between 0 to 0.52 means P(0 < z < 0.52)
which can be written as
P(0 < z < 0.52) = P(z < 0.52) - P(z < 0)
The probability of z score for 0 using z table is 0.5000 and the probability of z score for 0.52 is 0.6985
Therefore, P(0 < z < 0.52) = 0.6985 - 0.5000 = 0.1985
Therefore, the proportion of scores in a normal distribution between the mean (z = 0) and z = 0.52 is 0.1985
Need assistance solving problem. . > Moving to another question will save this response. Question1 What...
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