Homework Answers
We have to find P(-0.19<Z<3.02)
P(-0.19<Z<3.02)= P(-0.19<Z<0) + P(0<Z<3.02)
Since Z-Score (Standard Normal distribution is symmetrical about 0)
P(-0.19<Z<3.02)= P(0<Z<0.19) + P(0<Z<3.02) = 0.07534543 + 0.4987361= 0.5740816 ~ 0.57
Here Probability can be calculated by Z-table or in R.
> pnorm(0.19)-0.5
[1] 0.07534543
> pnorm(3.02)-0.5
[1] 0.4987361
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