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4. Approximate the number of moles of hydrogen peroxide at the equivalence point in the graph in the introduction, supposing thjs is the question


Thus the densities will be- Trial Mass(g) 0.448 0.450 3 Density(g/ml) 0.448 g/ 0.400 ml = 1.12 g/ml 0.450 g/ 0.400 ml = 1.125 this is the data



Background When hydrogen peroxide is mixed with bleach, oxygen gas is one of the producto experiment, you will measure the vo
The number of moles of bleach at the equivalence point is found using the density of the solution, which will be determined dthese are the background information


please help thank you
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Answer #1

3% (m/m) of H2O2 means,

(mass of H2O2)/(mass of solution)= 3%

Now, density of the solution from data = 1.11 g/ml (average)

Thus, 1ml solution = 1.11grams.

Thus, 1litre solution = 1.11*1000 = 1110 grams.

Now, mass of H2O2 = 3% * mass of solution = (3/100)* 1110 grams = 33.3 grams.

Thus, moles of H2O2= 33.3/MOLECULAR WEIGHT = 33.3/34.01 = 0.98 moles.

Thus, molarity of H2O2 = moles/volume in litre= 0.98/1 = 0.98M. (Ans)

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