Question

(b) (3pts) Using standard rules assign oxidation numbers to the various atoms in the following reaction: 4 PA + 7 S. ------>
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Answer #1

Oxidation state of P in reactant = 0

Oxidation state of P in product = +7

So, P is oxidised.

P4 is reducing agent

Oxidation state of Se in reactant = 0

Oxidation state of Se in product = -2

So, Se is reduced

Se is oxidising agent

Answer:

The substance oxidised is P

The substance reduced is Se

The oxidiizing agent is Se

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