Molar mass of P4 = 123.88 g/mol
mass(P4)= 3.39 g
use:
number of mol of P4,
n = mass of P4/molar mass of P4
=(3.39 g)/(1.239*10^2 g/mol)
= 2.737*10^-2 mol
Molar mass of Cl2 = 70.9 g/mol
mass(Cl2)= 28.4 g
use:
number of mol of Cl2,
n = mass of Cl2/molar mass of Cl2
=(28.4 g)/(70.9 g/mol)
= 0.4006 mol
Balanced chemical equation is:
P4 + 10 Cl2 ---> 4 PCl5
1 mol of P4 reacts with 10 mol of Cl2
for 2.737*10^-2 mol of P4, 0.2737 mol of Cl2 is required
But we have 0.4006 mol of Cl2
so, P4 is limiting reagent
we will use P4 in further calculation
Molar mass of PCl5,
MM = 1*MM(P) + 5*MM(Cl)
= 1*30.97 + 5*35.45
= 208.22 g/mol
According to balanced equation
mol of PCl5 formed = (4/1)* moles of P4
= (4/1)*2.737*10^-2
= 0.1095 mol
use:
mass of PCl5 = number of mol * molar mass
= 0.1095*2.082*10^2
= 22.79 g
Answer: 22.8 g
Question 3 1 pts What is the theoretical yield (in grams) of phosphorus pentachloride when 3.39...
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