Question

Question 1 1 pts Calculate the mass of potassium chloride, KCI, (in grams) formed when 7.00 g of chlorine gas is allowed to react with 5.00 g of potassium. (write the chemical reaction first) 7.36 7.38 14.7 4.77 9.53 Question 2 1 pts Carbon dioxide is produced in the following reaction: 5 H2C204(aq) + 2 KMnO4 (aq) + 3 H2SO4 (aq) → 10 CO2(g) + 2 MnSO4 (aq) + K2SO4 (aq) + 8 H20 (1) What is the limiting reagent when 3.12 g H2C2O4 reacts with 2.65 g KMnO4 with excess H2SO4? H2C204 MnSO4 OK2504 H2SO4 OKMnO4

Answer 1

Question 1 1 pts Calculate the mass of potassium chloride,KCI, din grams) formed when 7.00 g of chlorine gas is allowed to react with 5.00 g of potassium.write the chemical reaction first) 7.36 2K 7.38 14.7 + CI2 -----> 2KCI 5g/39g/mol 7g/71 g/mol O initial moles =0.1282 = 0.0986 K is the limiting reagent asitisless than twice of C12molest) 0.0986-0.1282/ 2 0 .1282/2=0.0641 thus moles of KCl formed = 0.0641 mass of KCI = moles x molar mass = 0.0641x74.5=4.775 g Question 2 1 pts Carbon dioxide is procuced in the following reaction: 5HXC0462 KM-O 3H2SO4 → 10 CO2 + 2 MnO4K_504 (+ EH_04 What is the limiting reagent when 312 g H.C_0.reacts with 2.45 g KMnO, with excess H 502 From the equals with 2 KM .65/158g/mol given to requi Mrso 3.125/90g/mol =0.346 2.65/158g/mol =0.01677 To know the limiting reagent find the ratio of given to required moles 0.346/5=0.0692 0.01671/2=0.00838 As KMnO4 ratio is smaller it is the limiting reagent. K, H.SO - IMr