Question

For the following reaction, 20.3 grams of chlorine gas are allowed to react with 4.10 grams of water. chlorine (g) + water (1) hydrochloric acid (aq) + chloric acid (HCIO3) (aq) What is the maximum amount of hydrochloric acid that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

3Cl + 3H₂0 - 5HQ + HClO laa) (9) 103 can nce 20.33= 0.286 mol 71 g/mol 0 H₂O = 4.1g - 0.228 mol 18 gimol from Nah - 3 - - Мно Ideally, nanho But, u ne> nH2O H₂O) is a limiting reagent Maximum amount of Hue - from 7 NHO - 5 NH2O Nhce = 5x0.228 moles, NHO = 0.38 mol MHQ = 0.38 X 36:5 MHU-36.5 mol g/mol mol/ MHU= 13.87 g 1 amount of che left = Na - NHO = 0.286-0-222 = 0.058 mol ma₂ = 0.058 8 x 71 g/mol mol ma=4-12 g

H2O is the limiting reagent

Cl2 is excess reagent