Solution- then distance is travels is y
0.5 mV^2 = Kq1q2*(1/r1-1/r)
1/r1-1/r = 0.5*4*10^-3*41^2/9*10^9*15*10^-6*2*10^-6
=12.45 m
1/r=(1/0.06)+12.45
r=3.43 cm
So,
v^2-u^2=2as
So, a= 41^2 -26^2 / (2*0.0343)
a=14.650*10^3 m/s^2
I hope help you !!
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