A charge of -2.95 μC is fixed in place. From a horizontal distance of 0.0484 m, a particle of mass 9.57 x 10-3 kg and charge -9.86 μC is fired with an initial speed of 58.1 m/s directly toward the fixed charge. How far does the particle travel before its speed is zero?
Using conservation of energy
Final electric potential energy = initial kE + initial electric potential energy
k q1 q2 / r = 0.5 m v^2 + k q1 q2 / R
(9 x 10^9) x (2.95 x 9.86 x 10^-12/r^2) = (0.5 x 0.00957 x 58.1^2) + (9 x 10^9 x 2.95 x 9.86 x 10^-12)/0.0484^2
Distance, r = 0.01214 m
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