Homework Answers
a) possible tickets = 54C6=25827165
P(winning)=1/25827165= 0.00000003872
b) P(winning $1595) = 6C5*48C1 / 54C6 = 288/25827165 =
0.000011151
c) P(lose) = P(0 ,1 or 2 number correct) = (48C6 + 6C1*48C5 +
6C2*48C4)/54C6 = 25464036 / 25827165 = 0.985940036
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