Question

calculate delta h neutralization in joules per mole for the reaction of 1.00 mol of hno3 with 1.00 mol of naoh

0.0 mL of 1.00M HNO, with 50.5 mL of 1.00M Calculate the heat transferred from the reaction of 50,0 mL of 1.00M HNO, with 50.5 ML OL NaOH solution. Assume the heat capacity of the mixture is 3.89 J 8 deg. (6) Calculate the number of moles of HNO, reacting when 50.0 mL of 1.00M HNO3 and 50.5 mL of 1.00M NaOH solution are mixed. (7) Calculate AH neuten in joules per mole for the reaction of 1.00 mol of HNO, with 1.00 mol of NaOH. (8) On the basis of an accepted AH neutzn of 58.5 kJ mol-' for the reaction, determine the percent error in your calculated AH neutzn % enor: 100% (expenmental value 58.5 kJ/mol 58.5 kJ/mol

Answer 1

Answer & Neutralization reaction: HNO3 (22.) + NaOH(aq.) → NaNO3 Caes) + H20(4) so 4 Hneuton - 1 molx Hj (NaNO3) 2927 + [1 molx «Hy*(H20)x] | - mol X H (HNO3)3%. - 1 mol X 4 H (M4OH)4. i molx -447.46 kJ/mol 7+ [1 mol X -285.83] - [1 mol X-207-36KT - [1 mol x - 470.11 kJ/mol] mol = – 55.82 kJ (4 Hy is standard enthalpy of formation) 4 Hneutrn 4 Hneuton per mol = moles of Naoh reacted moles of HNO3 reacted - 55.82 KJ 1.00 mol - – 55-82 KJ/mol