Question1 Charge +Q +1.10 nC is uniformly distributed along the right half of a thin rod...
+3.20 nC of charge is uniformly distributed along the top half of a thin rod of total length L = 3.40 cm, while -3.20 nC of charge is uniformly distributed along the bottom half of the rod, as shown in the figure, what is the magnitude of the electric field at the dot, a distance r= 20.0 cm from the centre of the rod?
Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in the figure (Figure 1).Part A Find an expression for the electric field E at the center of the semicircle. Part BEvaluate the field strength if L = 16 cm and Q = 38 nC
Question 1 -0 +0 Charge +Q +8.90 nC is unt rrnhy distributed along the right half of a thin rod bent nto a seno le of radius R-8.70 cm, whǐ charge-q = 90 nC is u f miy dstributed along the left half of the rod, as shown in the figure. What is the magritude and direction of the electric field at point P, the centre of the circle? Magnitude: Oirection, given as an angle measured counterclockwise from the positive...
Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semi circle shown in the figure (Figure 1) Evaluate the field strength if L=18 cm and Q=38 nC.
Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in the figure (Figure 1). Evaluate the field strength if L = 13 cm and Q = 21 nC . Express your answer with the appropriate units.
Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in the figure (Figure 1) . Evaluate the field strength if L = 15 cm and Q = 26 nC . Express your answer with the appropriate units.
Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in the figure (Figure 1).Part AFind an expression for the electric field \(\vec{E}\) at the center of the semicircle. Hint: A small piece of arc length \(\Delta s\) spans a small angle \(\Delta \theta=\Delta s / R,\) where R is the radius.Express your answer in terms of the variables Q, L, unit vectors \(\hat{i}, \hat{j},\) and appropriate constants.Part BEvaluate the field...
A thin glass rod forms a semicircle of radius r= 5.00 cm. Charge is uniformly distributed along the rod, with +q = 4.50 pC in the upper half and -q = -4.50 pC in the lower half. What are the: (a) Magnitude and: (b) Direction (relative to the positive direction of the x axis) of the electric field E at P, the center of the semicircle?
Answer with correct answer, 3 sig figs, and correct units, thank you! Safari Fille Edit View History Window Help LON-CAPA Part 2 Previous Tries Level 3 Complete the 2 questions below. Question1 -0 t0 Charge +Q-+4.70 nC is uniformly distributed along the right half of a thin rod bent into a semicirle of radus R·B 30 cm, while charge-Q·ー4.70 nC is uniform, distributed along the left half of the rod, as shown in the figure. What is the magnitude and...
1. Electric charge is distributed uniformly along a R thin rod of length a, with total charge Q. Take the у potential to be zero at infinity e a. Find the electric field Ē at point P, a distance x to the right of the rod (10 pts) b. Find the electric field Ē at point R, a distance y above of the rod (10 pts) c. In parts (a) and (b), what does your result reduce to as x...