Homework Answers
------- H2C6H6O6(aq) + H2O(l) ------------> HC6H6O6^- (aq) + H3O^+ (aq)
I -------- 0.235 ------------------------------------ 0 ----------------- 0
C ------ -x ------------------------------------------- +x -----------------+x
E ----- 0.235-x --------------------------------- +x ---------------- +x
Ka1 = [HC6H6O6^-]{H3O^+]/[H2C6H6O6]
7.9*10^-5 = x*x/(0.235-x)
7.9*10^-5*(0.235-x) = x^2
x = 0.0043
[HC6H6O6^-] = x = 0.0043M
[H3O^+] = x = 0.0043M
HC6H6O6^- (aq) + H2O(l) ---------------> C6H6O6^2- (aq) + H3O^+ (aq)
Ka2 = [C6H6O6^2-][H3O^+]/[HC6H6O6^-]
1.6*10^-12 = [C6H6O6^2-]*0.0043/0.0043
[C6H6O6^2-] = 1.6*10^-12M>>>answer
PH = -log[H3O^+]
= -log0.0043
= 2.3665
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