Question

R 12:30-t45 (585) Spg 2019 (2192) Quiz 6:Chapters 8,n 6 of 8 Time R Gen Matrimony Monthly is a top-selling magazine that provides information for couples thinking about marriage. Over the years, witers for the magazine have researched just about everything there is to research about wedlings. The popular conceptšion at the mogazine has been that roughly 50% af frst weddings take place indoors in a church, 30% take place indoors in a building other than a church, and 20% take place outdoors. This past week, the examined a random sample of 250 first weddings and found the di given in the first row of numbers in Table 1 below. (This row contains the frequencies observed in their sample of 250.) The second row of numbers in Table 1 gives the frequencies expected under the hypothesis that the is correct. The bottom row of numbers in Table 1 contains the values (Observed frequency -Expected frequency) Expected frequency for each of the wedding location categories. There is now some disagreement among employees that any differences between the two are due to chance Fill in the missing values of Table 1. Then, using the 0.10 level of significance, perform a test of the hypothesis that the actual distribution of first wedding of the magazine. Some say that this sample demonstrates that the actual location distribution of first t in the magazine's popular conception; others maintain that the sample data accord with the magazine's popular conception and locations matches the distribution in the magazine's popular conception. Then complete Table 2 Round your responses for the expected frequencies in Table 1 to at least two decimal places. Round your decimal places. Round your responses in Table 2 as specified. In a church a church Observed freq 151 62 37 250

Where it says “the type of test statistic , chose one) the options are Z, t , Chi square , F”

Answer 1

	Oi	Ei	(Oi-Ei)^2/Ei
0.5	151	125	5.408
0.3	62	75	2.253333333
0.2	37	50	3.38
1	250	TS	11.04133333
		critical	5.991464547
		p-value	0.004003178

a)
type of TS = chi-square

TS = 11.0413
p-value = 0.0040

p-value < alpha
hence yes

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