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STA2023-TR 12 30-145 (1585) Spg 2019 (2192) More than one teacher has given the following advice: choose answer C when blindly guessing among four answers in a multiple choice test, since c is more often the correct answer than either A, B, or D Suppose that we take a random sample of 560 multiple-choice test answers (the correct answers from the instructors answer sheet) from introductory college courses and obtain the information summarized in the first row of numbers in Table 1 below. These numbers are the observed frequencies for each of the categories correct answers if a correct answer is equally likely to be A, B, C, or D、The bottom row of numbers in Table i contains the values A, B, C, and D for our sample of 560 correct answers. The second row of numbers in Table 1 contains the frequencies expected for a sample of 560 O-E) (Observed frequency-Expected frequency)2 Expected frequency for each of the correct answer categories A, B, C, and D. Fill in the missing values of Table 1. Then, using the 0.05 level of significance, perform a test of the hypothesis that each of A, B, C, and D is equal y likely to be the correct answer on tests in these introductory college courses. Then complete Table 2. Round your responses for the expected frequencies in Table 1 to at least two decimal places. Round your decimal places. Round your responses in Table 2 as specified. responses in Table 1 to at least three Table 1t Information about the Sample Correct answer TC Total
5) Spg 2019 (2192 Quiz 6: Chapters 8, 11 1 of 8 Time Remaining 1:1312 Table 1: I C Total 136 560 140.00 140.00 Co-1) 1.829 0.114 The value of the test statistic: (Round your answer to at least two decimal places.) Can we reject the hypothesis that A, B, C, and D are equally likely to be No the correct answer ontests in these introductory college courses? Use the 0.05 level of significance. | O Yes
Where it says “the type of test statistic” the options are “Z , t , Chi square , or F” thanks!
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Answer #1
p Oi fi (Oi-Ei)^2/Ei
0.25 149 140 0.578571429
0.25 151 140 0.864285714
0.25 124 140 1.828571429
0.25 136 140 0.114285714
1 560 560 3.385714286
TS 3.385714286
critical value 7.814727903
p-value 0.335889872

type = chi-square
TS = 3.3857
p-value = 0.3359

No

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