Number of moles of OH- solution 1 = (0.0058mol/1000ml) × 1.10ml = 6.38 ×10-6mol
Number of moles of OH- solution 2 = (0.0036mol/1000ml) × 9.00ml = 3.24 ×10-5mol
Total number of moles of OH- = 0.00003878mol
Total volume = 10.10ml
[OH-] = (0.00003878mol/10.10ml) ×1000ml = 0.003840M
pOH = - log[OH-]
pOH = - log(0.003840M)
pOH = 2.42
pH = 14 - pOH
pH = 14 - 2.42
pH = 11.58
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