I know the answer is 1.86 M, but I'm not sure how to get it.
Homework Answers
So the dilution formula to find the molarity Ca2+ and Mg2+ is:
M1V1 = M2V2
Here M1= 0.7044M
V1= 27.35-1= 26.35ml as 1ml blank required.
M2=?
V2= 10ml
On substituting, M2= 26.35ml * 0.7044M/ 10ml= 1.86M
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a standard solution containing 0.01500 M Ca2+ required 42.87 mL of EDTA to reach the endpoint. The molarity of the EDTA solution is: ________ M b) That same EDTA solution was then used to titrate an unknown hard water sample. A 40.00 mL aliquot of unknown hard water required 34.21 mL of EDTA solution to reach a distinct endpoint. The concentration of Ca2+ ions (assuming...
Please help. I will rate! A 0.4721 g sample of pewter, containing tin, lead, copper, and...
Please help. I will rate!
A 0.4721 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO 4 H,O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 34.45 mL of 0.001518 M EDTA. Thiosulfate was used to mask the copper in...
Please help! Will rate. A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of Caco, is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of Caco, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca2+ in the 250 mL of solution? c. How many moles of Caare in a 25.00-mL aliquot of the solution in...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+ and Mg^2+ in a 100.0-mL aliquot of the diluted solution required 20.81 mL of 0.00830 M EDTA, after being buffered to a pH of 10.0. The Ca^2+ second 100.0-mL aliquot was precipitated as CaC_2O_4(s), which was filtered and washed. The filtrate and washings were titrated with 5.98 mL of the EDTA solution. Calculate the milligrams of Ca^2+ and Mg^2+ in the 24-hr sample.
I know that i must make an ice chart and when i do, i get zero for both of the products.
I know that i must make an ice chart and when i do, i get zero
for both of the products.
11. Ethylenediamminetetraacetic acid (EDTA ) binds metals ions to form complexes, thus can be used to determine concentrations of metal ions, as well as for use in chelation therapy. Calculate the concentration of [Co2] in solution after the addition of 48.0 mL of 0.050 M EDTA to a 50.00-ml sample of 0.048 M [Co]. 10 pts
11. Ethylenediamminetetraacetic acid...
I need help solving this problem. I know the answer but i'm not sure how to...
I need help solving this problem. I know the answer but i'm not
sure how to work it out. Thanks!
18./The pediatric dose of cefadroxil is 30 mg/kg/day. If a child was given a daily dose of 2 teaspoonfuls of a pediatric suspension containing 125 mg of cefadroxil per 5 mL, what was the weight, in pounds, of the child?
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2...
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2 and then, Ca2* was titrated at pH 13 with 9.25 ml of the same EDTA solution. Calculate ppm CaCo, (FW-100.09) and MgCO, (FW-84.31) in the sample. FWca: 40.08; FWm: 24.30
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10....
4. A 2.86 g sample containing both Fe and V was dissolved under certain conditions and diluted to 200.00 mL. Fe2 and VO ions. The titration of this solution required 22.64 mL of0.1000 M Ce" t...
4. A 2.86 g sample containing both Fe and V was dissolved under certain conditions and diluted to 200.00 mL. Fe2 and VO ions. The titration of this solution required 22.64 mL of0.1000 M Ce" to reach end point. A second 50.00 mL aliquot was passed through a Jones reductor to forn ions. The titration of the second solution required 42.66 mL of 0.1000 M Ce solution to reach an end point. Calculate the percentage of Fe and V in...
how would I calculate my results from the first two data the first data is my...
how would I calculate my results from the first two data the
first data is my results and the second data I have to calculate
each of those with the information that I have on the first 3
trails I really really need help and i just dont understand thank
you.
1 concentration of EDTA solution 2 molar mass of CaCO3 0.0100 M 100.09 g/mol Trail 1 -Trail 2 Trail 3 12 12.01 11.99 5 Unknown analysis Part 1 (pH...
Please help. I will rate!
A 0.4721 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO 4 H,O and removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 34.45 mL of 0.001518 M EDTA. Thiosulfate was used to mask the copper in...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
Name Section Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of Caco, is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of Caco, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca2+ in the 250 mL of solution? c. How many moles of Caare in a 25.00-mL aliquot of the solution in...
A 24-hr urine specimen was diluted to exactly 2.000 L in a volumetric flask. The Ca^2+ and Mg^2+ in a 100.0-mL aliquot of the diluted solution required 20.81 mL of 0.00830 M EDTA, after being buffered to a pH of 10.0. The Ca^2+ second 100.0-mL aliquot was precipitated as CaC_2O_4(s), which was filtered and washed. The filtrate and washings were titrated with 5.98 mL of the EDTA solution. Calculate the milligrams of Ca^2+ and Mg^2+ in the 24-hr sample.
I know that i must make an ice chart and when i do, i get zero
for both of the products.
11. Ethylenediamminetetraacetic acid (EDTA ) binds metals ions to form complexes, thus can be used to determine concentrations of metal ions, as well as for use in chelation therapy. Calculate the concentration of [Co2] in solution after the addition of 48.0 mL of 0.050 M EDTA to a 50.00-ml sample of 0.048 M [Co]. 10 pts
11. Ethylenediamminetetraacetic acid...
I need help solving this problem. I know the answer but i'm not
sure how to work it out. Thanks!
18./The pediatric dose of cefadroxil is 30 mg/kg/day. If a child was given a daily dose of 2 teaspoonfuls of a pediatric suspension containing 125 mg of cefadroxil per 5 mL, what was the weight, in pounds, of the child?
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2 and then, Ca2* was titrated at pH 13 with 9.25 ml of the same EDTA solution. Calculate ppm CaCo, (FW-100.09) and MgCO, (FW-84.31) in the sample. FWca: 40.08; FWm: 24.30
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10....
4. A 2.86 g sample containing both Fe and V was dissolved under certain conditions and diluted to 200.00 mL. Fe2 and VO ions. The titration of this solution required 22.64 mL of0.1000 M Ce" to reach end point. A second 50.00 mL aliquot was passed through a Jones reductor to forn ions. The titration of the second solution required 42.66 mL of 0.1000 M Ce solution to reach an end point. Calculate the percentage of Fe and V in...
how would I calculate my results from the first two data the
first data is my results and the second data I have to calculate
each of those with the information that I have on the first 3
trails I really really need help and i just dont understand thank
you.
1 concentration of EDTA solution 2 molar mass of CaCO3 0.0100 M 100.09 g/mol Trail 1 -Trail 2 Trail 3 12 12.01 11.99 5 Unknown analysis Part 1 (pH...
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