I know that the answer is a but what are the steps ?? 09 A particle...
I know that the answer is a but what are the steps of solving it?? Q4 The velocity of a particle moving along the x-axis is given, for0, by (50r - 2.0r') m/s, where is in s. What is acceleration of the particle (after0) when it achieves its maximum displacement in the positivex-direction? A) -1.0x102 m/s2 B) -1.9x102 m/s2 C) +1.9x102 m/s2 D) +1.0x102 m/s2 E) -1.5x102 m/s2
A particle starts from the origin at t = 0 with a velocity of (8.3j hat) m/s and moves in the xy plane with a constant acceleration of (3.2i hat + 1j hat) m/s2 . At the instant the x coordinate of the particle is 29 m, A. what is the value of its y coordinate and B. its speed
A particle starts from the origin at t Owith a velocity of 6.2j and moves in the xy plane with a constant acceleration of (5.2i +2.6j) m/s2. At the instant the particle's x coordinate is 29 m, what are (a) its y coordinate and (b) its speed? (a) Number Unitsm (b) Number Units m/s
At t = 0, a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0i - 4.0j)m/s2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? 10 m/s 16 m/s 12 m/s 14 m/s 26 m/s
At t = 0, a particle leaves the origin with a velocity of 9 0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0i - 4.0j)m/s^2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? 10m/S 16 m/s 12 m/s 14 m/s 26 m/s
At t = 0 s, a particle starts from the origin of a coordinate system and moves in the xy plane with a velocity ~v = (7.9ˆi − 3.2ˆj) m/s. Determine the x position of the particle at t = 2.0 s.
A 1.30-kg particle moves in the xy plane with a velocity of V - (3.90 i 3.20j) m/s. Determine the angular momentum of the particle about the origin when its position vector is r-(1.50i2.20 j) m. R)kg m2/s
Course Contents »> > Problem Set 3Timer Notes Evaluate Feedback Print Info particle leaves the origin with an initial velocity of 5.00 m/s in the x direction, and moves with constant acceleration a -2.00 m/s and ay 2.70 m/s2. How far does the particle move in the x direction before turning around? Submit Answer Tries O/8 What is the particle's velocity at this time? Enter the x component first, followed by the y component. Submit Answer Tries 0/8
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.60 s, the particle's velocity is vector v = (8.90 i + 7.70 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.70 s, the particle's velocity is vector v = (7.40 i + 6.90 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...