With an initial velocity of 17 m/sec at a 70 degree angle, what is the maximum...

Question

Question

With an initial velocity of 17 m/sec at a 70 degree angle, what is the maximum height of a canonball shot from a cannon?

Answer 1

Answer #1

Maximum height, h = u^2 (sin(theta))^2/2g

h = 17^2 x (sin70)^2/ 2 x 9.8 = 13.02 m

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Answer 2

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