Question

PartA Constants If the flare is fired at an angle of 48.0° above the horizontal on the level salt flats of Utah, what is its horizontal range? You can ignore air resistance A pistol that fires a signal flare gives the flare an initial speed (muzzle speed) of 150 m/s ΑΣφ km Submit ▼PartB If the flare is fired at the same angle over the flat Sea of Tranquility on the moon, where g 1.6m/s, what is its horizontal range? km

Answer 1

Initial speed, $u=150m/s$

$\theta =48^{\circ}$

Range ,$R=u^{2}sin2\theta /g$

$R=(150m/s)^{2}sin2*48 /(9.81m/s^{2})$

$R=150^{2}sin96/9.81$

Part A) ANSWER: ${\color{Red} R=2281m}$

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Part B) g=1.6m/s²

Initial speed, $u=150m/s$

$\theta =48^{\circ}$

Range ,$R=u^{2}sin2\theta /g$

$R=(150m/s)^{2}sin2*48 /(1.6m/s^{2})$

$R=150^{2}sin96/1.6$

ANSWER: ${\color{Red} R=13985.5m}$

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