a) Xcm = (m1d1 + m2(d1+d2) + m3(d1+d2+d3))/(m1+m2+m3)
You need to use proper brackets or parantheses.
b) (22*1.5+11*(1.5+1.6)+42*(1.5+1.6+3.9))/(22+11+42) = 4.814 cm
c) Xcm = (-m1d2+m3d3)/(m1+m2+m3)
Part A-C. Please note I’ve attempted A many times so be sure to not write the...
As you can see part A gave you the answer so just use it to answer the rest of the questions. Zoom to see clearly. Thanks pleted pleted m1 24 g, is placed a distance d 1.1 cm from the left end of the rod. The second bead, of mass 2 sa 11 g, is placed a distance dh 18 am to the right of the first bead. The third bead, of mass m 42 g, is placed a distance...
3 part question G a rock of mass mis 135 k X Chapter 8- Momentum x theexpertta.com/Common/TakeTutorialAssignment.aspx T (13%) roblem 8. Three beads are placed on the vertices of an equi triangle of side d 1.5 cm. The first bead of mass mu 135 g is placed on the top vertex. The second bead of mass m 55 g is placed on the left vertex The third bead of mass m3 85 g is placed on the right vertex. otheexpertta.com...
Please do part A , B and C . Zoom to see clearly. Thanks Class Management Help Reading Quiz C4 Begin Date: l19/2017 12:01:00 AM Due Date: 1/312017 2:00:00 PM End Date: 5/31/2017 10:00:00 AM 000%) Problem i: The three figures below show two small balls, of masses mi 1.8 kg and A) v m2 6.5 kg. 14 cm from the origin. What is thexcomponent of the center ofmass tus tus 4 33% Part (a) In figure (A), the po...
answer b please. I dont need part a i got that already. i tried to solve b but my answr was wrong. 092619 LifeHist-BIO 3250 a Amazoncom: Watch The Ka The Expert TA | Human x + v thttps//usb06ca.theexpertta.com/Common/TakeTutorialAssignment.aspx Cass Mansgement HW chapter 3 Begin Date: 9/5/2019 12:01:00 AM- Due Date: 9/14/2019 11:59:00 PM End Date: 12/31/2019 11:59:00 PM (9%) Problem 11: has a velocity of 2.1 m/s in a direction 33° east of north relative to the Earth. It...
Part A lorqnes and Angelar Momentum Begin Date: 1/28/2019 12:00:00 AM-Due Date: 1/30/2019 11:59.00 PM End Date: 2/14/2019 11:00:00 (6%) Problem 11: Penny is adjusting the psition of standuppiro of mass-245-en kg im her living room. The piano is ip 14m in length. The piano is currently at an angle of o 54 degrees to the wall. Penny wants to rotate the piano across the carpeted loor so that it is flat up against the wall. To move the piano,...
I need help with the diagram in part c!! 12:31 PM Wed Apr 29 1 99% co 3. A rod of length 30.0 cm has linear density (mass-per-length) given by 1 = 50.0 g/m +20.0 x g/m², where x is the distance from one end, measured in meters. (a) What is the total mass and the location of the center of mass as measured from the x=0 left end? YOU MAY USE THE RESULTS FROM QUIZ 8 (b) Find the...
please solve part a and b w explanations thank you Class Management | Help HW 8 Begin Date: 11/18/2019 12:01:00 AM --Due Date: 11/25/2019 11:59:00 PM End Date: 12/15/2019 11:59:00 PM (8%) Problem 12: Light of wavelength 2 is incident on a single slit of width W 8.7 um. On a screen placed a distance L 0.44 m behind the slit the first dark fringe is located at a distance of D-0.035 m from the central bright fringe. 50% Part...
Part A is completed (0.205). I need parts B and C (circled in yellow). Incorrect answers which I tried are circled in red (6%) Problem 16: A rod of niass M-3.05 krt and length L can rotate about a lunge at sts left end and is initially at rest. A putty ball of mass m5s g, moving with speed v 6.86 m/s, strikes the rod at angle 0- 39 from the normal at a distance D 23 L, where L...
PART C AND PART D Class Management Help HW10: Oscillatory motion and waves (Chapter 16) Begin Date: 10/31/2019 3:00:00 PM - Due Date: 11/20/2019 11:59:00 PM End Date: 12/18/2019 11:59:00 PM (0%) Problem 7: The length of nylon rope from which a mountain climber is suspended has a force constant of 1.55 x 10' N/m. Randomized Variables km 1.55 x 10 N/m theexpert.com-triking id: 51-ES-D-A685-17564. In scordance with Expert TA Terms of Service copying this information to any solutions sharing...
amework 1 Begin Date: 1/16/2019 12 01 00 AM (1 Due Date: 1/27/20 19 11 S9 00 PM End Dat 1756) Problem 2: A mass m- 11kg is at the end of a hor zontal prug ofspr ng constant k. 21S Nano af surface. The block is palled, stretching the spring a distance A 5.5 cm from equilibrium, and released from rest taleis zontal ヅ17% Part (a) Write an equation for the angular fequency ω ofthe oscillation ψ 17% Part...