I need help with the diagram in part c!!
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I need help with the diagram in part c!!
12:31 PM Wed Apr 29 1 99%...
A rod of length 30.0 cm has linear density (mass per length) given by: d =...
A rod of length 30.0 cm has linear density (mass per length) given by: d = 50.0 20.0 x where x is the distance from one end, measured in meters and A is in kg/meter. (a) What is the mass of the rod? (b) How far from the x-0 end is its center of mass?
need help with the FBD, the unknowns, and L1 and L2 thank you In this case...
need help with the FBD, the unknowns, and L1 and L2
thank you
In this case both top and bottom supports of the PVC pipe are fixed. There is only one lever arm at the center of the pipe where torque is caused by applying weights of 5 N on each side of the hanger. Place dial gage at the point where load is applied to measure the deflection caused by it. After making the initial reading zero on the...
Consider the pendulum bob shown. The bob is constructed from a flat disk of mass 2.50...
Consider the pendulum bob shown. The bob is
constructed from a flat disk of mass 2.50
kg and diameter 20.0 cm which is connected to a rod of length 30.0
cm and mass of 2.00 kg.
The bob rotates about a pivot on end of the rod that is parallel to
the ground.
a. Find the total gravitational torque acting on the
bob when it is at an angle of 25.0° below the
horizontal.
b. Use the parallel axis theorem...
I need help with my physics homework
A beam resting on two pivots has a length of L = 6.00 m and mass M = 85.3 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivotplaced a distance l = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 54.8 kg steps onto the left end of the beam and begins walking to theright as in the figure below. The...
I understand part a, but I am getting the incorrect answers for b and c. The...
I understand part a, but I am getting the incorrect answers for
b and c.
The answer to b is 12.7 rad/s, the answer to c is 0.44 kgm^2/s.
Please show all work including which general equations you are
using to set up the problem, thank you!
Prob 2 A "one-dimensional" rod (no width to consider) of mass M-3.2 kg and length-0.18 mis nailed to a wall at one end, having a moment-of-inertia o- 0.035 kgm2 about that axis. The...
PART A PART B PART C Q14 (10 points): If the rotational inertia about an axis...
PART A
PART B
PART C
Q14 (10 points): If the rotational inertia about an axis through the midpoint of one end of the slab, axis 1 in the below figure, is 4.7x104 kg.m2, what is its rotational inertia about the axis through its center of mass, axis 2? Mass of the slab is 0.16 kg. (Hint: Use parallel-axis theorem.) Answer: I-3.26x I0 kgm2 a 2 cm -бст Q19 (10 points): A square slab of 0.4 m on each side...
the question is in last picture. i provided the lab content... I need guidance. thank you....
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
1. What is the angular momentum of a 0.240-kg ball rotating on the end of a...
1. What is the angular momentum of a 0.240-kg ball rotating on the end of a thin string in a circle of radius 1.35 m at an angular speed of 15.0 rad/s ? 2. A diver can reduce her moment of inertia by a factor of about 4.0 when changing from the straight position to the tuck position. If she makes 2.0 rotations in 1.5 s when in the tuck position, what is her angular speed (rev/s) when in the...
Rotational Dynamics Assignment (200 Points) • Due Friday, July 31 at 5:00 pm Equations are in...
Rotational Dynamics Assignment (200 Points) • Due Friday, July 31 at 5:00 pm Equations are in a separate document entitled “Equations for Rotational Dynamics Assignment” • Moments of inertia formulas are provided on the last page of this document • Show all of your work when solving equations. It is not sufficient to merely have a correct numerical answer. You need to have used legitimate equations and algebra. You also need to have correctly used the data. • Units must...
Just need help filling in the blanks! Thank you. Part 1: Three Levers In this part,...
Just need help filling in the blanks! Thank you.
Part 1: Three Levers In this part, you will set up a lever in three different configurations. First Lever The first is straightforward: set up the plastic ruler so that it pivots about its center. Apply two forces (resulting in two torques) to it as shown. Torque 1: Torque 2: Place a hanger (20 grams) in the first hole to the left of center and add 200 grams to it. Place...
A rod of length 30.0 cm has linear density (mass per length) given by: d = 50.0 20.0 x where x is the distance from one end, measured in meters and A is in kg/meter. (a) What is the mass of the rod? (b) How far from the x-0 end is its center of mass?
need help with the FBD, the unknowns, and L1 and L2
thank you
In this case both top and bottom supports of the PVC pipe are fixed. There is only one lever arm at the center of the pipe where torque is caused by applying weights of 5 N on each side of the hanger. Place dial gage at the point where load is applied to measure the deflection caused by it. After making the initial reading zero on the...
Consider the pendulum bob shown. The bob is
constructed from a flat disk of mass 2.50
kg and diameter 20.0 cm which is connected to a rod of length 30.0
cm and mass of 2.00 kg.
The bob rotates about a pivot on end of the rod that is parallel to
the ground.
a. Find the total gravitational torque acting on the
bob when it is at an angle of 25.0° below the
horizontal.
b. Use the parallel axis theorem...
I understand part a, but I am getting the incorrect answers for
b and c.
The answer to b is 12.7 rad/s, the answer to c is 0.44 kgm^2/s.
Please show all work including which general equations you are
using to set up the problem, thank you!
Prob 2 A "one-dimensional" rod (no width to consider) of mass M-3.2 kg and length-0.18 mis nailed to a wall at one end, having a moment-of-inertia o- 0.035 kgm2 about that axis. The...
PART A
PART B
PART C
Q14 (10 points): If the rotational inertia about an axis through the midpoint of one end of the slab, axis 1 in the below figure, is 4.7x104 kg.m2, what is its rotational inertia about the axis through its center of mass, axis 2? Mass of the slab is 0.16 kg. (Hint: Use parallel-axis theorem.) Answer: I-3.26x I0 kgm2 a 2 cm -бст Q19 (10 points): A square slab of 0.4 m on each side...
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
Rotational Dynamics Assignment (200 Points) • Due Friday, July 31 at 5:00 pm Equations are in a separate document entitled “Equations for Rotational Dynamics Assignment” • Moments of inertia formulas are provided on the last page of this document • Show all of your work when solving equations. It is not sufficient to merely have a correct numerical answer. You need to have used legitimate equations and algebra. You also need to have correctly used the data. • Units must...
Just need help filling in the blanks! Thank you.
Part 1: Three Levers In this part, you will set up a lever in three different configurations. First Lever The first is straightforward: set up the plastic ruler so that it pivots about its center. Apply two forces (resulting in two torques) to it as shown. Torque 1: Torque 2: Place a hanger (20 grams) in the first hole to the left of center and add 200 grams to it. Place...
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