Solution:
The given test are performed for the analysis of anion.
1) Addition of 1M HCl
Bubbles forms which confirms the evolution of CO2 gas.
Hence, CO3^2- present.
2) BaCl2 test
Confirms the formation of white precipitate of BaSO4.
Hence, SO42- present.
3) Addition of AgNO3
If Cl- or SCN- ions are present, it gives white precipitate.Since, a clear solution is observed, hence confirms the absence of both Cl- ans SCN-.
Hence, Cl- and SCN- absent.
Thus,
CO3^2- = P
SO4^2- = P
Cl- = A
SCN- = A
Fe3+ = U
Cu2+ = U
Al3+ = U
PO43- = U
An unknown that might contain any of the elght lons studied in this experiment but no...