here,
the height of cliff , h = 23.6 m
v0 = 13.5 m/s
theta = 26.5 degree
let the time taken to hit the ground be t1
for first stone
- h = v0 * t1 * sin(26.5) - 0.5 * g * t1^2
- 23.6 = 13.5 * t1 * sin(26.5) - 0.5 * 9.81 * t1^2
solving for t1
t1 = 2.89 s
let the time taken to hit the ground be t2
for second stone
- h = - v0 * t2 * sin(26.5) - 0.5 * g * t2^2
- 23.6 = - 13.5 * t2 * sin(26.5) - 0.5 * 9.81 * t2^2
solving for t2
t2 = 1.66 s
the difference between the horizontal distance , x = v0 * cos(theta) * ( t1 - t2)
x = 13.5 * cos(26.5) * ( 2.89 - 1.66)
x = 14.86 m
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