Question

(7) A conducting spherical shell of radius r is charged to a potential V. What is the value of the potential at a distance D from the surface of the sphere? (10 pts)
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Answer #1

Given is:-

Radius of the conducting spherical shell = r

Potential = V

Now,

we know that

Ky v 7 or 4TEoT

Solving for charge q we get

q = 4 pi epsilon_o r (V) eq-1

Now,

By Gauss's law the potential at a distance D from the surface will be

V' = rac{1}{4 pi epsilon_o} rac{q}{D}

by substituting the value of q from eq-1, we get

14TErV)

which gives us

VD

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