Question

0.5 points QUESTION 3 Save Answer Zinc reacts with aqueous sulfuric acid to form hydrogen gas: Zn (s)H2SO4 (aq)ZnSO4 (aq) + H2 (g) In an experiment, 225 mL of wet Hp is collected over water at 27 °C with a total pressure of the water-hydrogen mixture of 748 torr. The vapor pressure of water at 27 °C is 26.74 torr How many grams of Zn have been consumed? 431 O 0.567 4.31 x 105 O567 4.79 x 106 0.5 points QUESTION 4 Save Answer The reaction of 50 mL of N2 gas with 150 mL of H2 gas to form ammonia via the equation: N2 (g)3H2 (g)-» 2NH3 (g) mL of ammonia if pressure and temperature are kept constant will produce O 150

Answer 1

Zn(s) + H₂sou laa) > 2ossoulaq) + H218) V = volume of wat H om = 2250m2 V = 225 mls 0.225L V = 0.2252 Temperature =T=27°C = 300k Ti=book wet H₂ vаbоu means (v, o). Hq qas containing water Tefal Pressure of wet Hq = 748 forr = Proff Ptopal = 748 forr = 748 am 760 -0.984 alm. (760forra latom} p= Pratal = 0.984 asm. na tofal no. of moles of I wet Hz. 0 0 kons - PranRT ) na PV R=0.0821 Lakh RT ) mok n. 1 lu RT - ? (0.984 afto) x 10.225k) __ 0.0821 Kaps. mottat 3 2012 na 8.99 X10-3 moli Page No.

tefal moles of met H₂= n=8.998 10-3 mol. Пон, - vapour pressure of H eater & at 27°C = partial pressure of Hao at 27% = 26.74 forr - PHgo = partial pressure of H2O = 26.77 foor __ Тие од 24 - 4 am googs2 fm 60 е 003592 от I partial pressure of more fraction of hultafel 4 - 1 Среща = partial pressure of Иg o vbви | moles faction le ей, о vbл ) і ух до :) Prze = 1 X 430) x brosant 1) (- 0352 4)- (ху, ) х (о" 494 «һ» ) 2 б. 038 Page No. |

oo3 S8 mole motes of H2O raporu fraction el Hooropour tefal molesef met Hy gay | mоu qИ, o veb sa) ) три 4 и, о р Ф4 Х. an - (o-ozgx 8.44x1ъ3 ) mol со. 322xip-3 от 1 m oleg 4 Иy o vbow - о: 322 x163 от v1. moles of hy gas = tefal mores) - /moly of 1 Horapour) (e: 99x) 3 — 6: 322x703) 2 2 - 67 Хро-3 m of.

8.6f810-3 mol moles of Hq gas = for Reaction - Zn(s) + Ho soy lag > Znoy (ag) + H₂ (g) from reaction- imal Ho produced from imal of an - consumption oo gobf810-3 mol will produce from = = 18 10 3 x 8.67 mol of moles of Zn consumed = 8.67816-3 mor mass of En consumed a more) x molar 1 m9557 = 8.68x10-3 m/or x 65ogg - 567.02 X 10-39 - 0.567 g mass of an consumed = 0.567g