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Zinc reacts with hydrochloric acid to form hydrogen gas. A 0.258 g sample of Zinc reacts...
zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)ZnCl2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 745 mm Hg. If the wet H2 gas formed occupies a volume of 9.32 L, the number of moles of Zn reacted was __mol. The vapor pressure of water is 17.5 mm Hg at 20 °C.
Hydrogen gas is produced by the reaction of hydrochloric acid, HCl, on zinc metal. 2HCl (aq) + Zn (s) --> ZnCl2 (aq) + H2 (g) The gas is collected over water. If 106 mL of gas is collected at 28C and 775 mmHg, what is the mass of hydrogen collected? (vapor pressure of water at 28C is 25.6 mmHg)
When 0.40 g of impure zinc reacted with excess hydrochloric acid, 127mL of hydrogen gas were collected over water at 10 degrees C at a total pressure of 737.77 Torr. The vapor pressure of water at 10 degrees C is 9.21 Torr. The reaction in question is: Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (aq) A.) what amount (in grams) of H2 gas was collected? B.) what is the percentage of purity of the zinc, assuming that...
Zinc metal reacts with hydrochloric acid (HCI) according to the equation: Zn(s) + 2HCl(aq) - ZnCl(aq) + H2(g) Part A How many grams of hydrogen are produced if 300 g of zinc reacts? AEP O ? M . Submit Request Answer
please help Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g How many milliliters of 4.50 M HCl(aq) are required to react with 5.25 g of an ore containing 50.0% Zn(s) by mass? Number mL
Zinc reacts with hydrochloric acid according to the reaction equation Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2HCl (aq) rightarrow ZnCl_2 (aq) + H_2 (g) How many milliliters of 3.50 M HCI(aq) are required to react with 8.45 g of an ore containing 21.0% Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 2.65 g of an ore containing 26.0 % Zn(s) by mass? volume: mL
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 2.00 M HCl(aq)2.00 M HCl(aq) are required to react with 8.55 g Zn(s)?
Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation: Zn(s) + 2HCl(aq)>ZnC2(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 749 mm Hg. If the wet H2 gas formed occupies a volume of 8.34 L, the number of grams of H2 formed is g. The vapor pressure of water is 17.5 mm Hg at 20 cc. Submit Answer Retry Entire Group...
Zinc metal reacts with hydrochloric acid according to the balanced equation: 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g) When 0.103 g of zinc is combined with enough HCl to make 50.0 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, resulting the temperature of the solution from 22.5oC to 23.7 oC. Find ΔHrxn for this reaction as written. The density, and the specific heat of the solution are 1.00 g/mL and 4.184 J/g...