From the equation you see one mole zinc react with two mole hydrogen chloride to form one mole zinc chloride and one mole hydrogen.
Molecular weight of zinc 65.38 that is one mole Zn
30 gm zinc means 30÷65.38=0.46 mole
So .46 mole zinc will react with (.46×2) mole hydrogen chloride to produce .46 mole zinc chloride and .46 mole hydrogen gas.
So the hydrogen produce =.46 mole= (.46×2)= .92 grams.
Zinc metal reacts with hydrochloric acid (HCI) according to the equation: Zn(s) + 2HCl(aq) - ZnCl(aq) + H2(g) Part...
Zinc reacts with hydrochloric acid according to the reaction equation: Zn (s) + 2HCl (aq) → ZnCl₂ (aq) + H₂ (g) How many milliliters of 3.00 M HCl (aq) are required to react with 5.95 g of an ore containing 42.0% Zn (s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 2.00 M HCl(aq)2.00 M HCl(aq) are required to react with 8.55 g Zn(s)?
please help Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) +2HCl(aq) ? ZnCl2(aq)-H2(g How many milliliters of 4.50 M HCl(aq) are required to react with 5.25 g of an ore containing 50.0% Zn(s) by mass? Number mL
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 6.50 M HCl(aq) are required to react with 4.45 g of an ore containing 39.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 4.00 M HCl(aq) are required to react with 7.15 g of an ore containing 43.0 % Zn(s) by mass?
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.50 M HCl(aq) are required to react with 2.95 g of an ore containing 43.0 % Zn(s) by mass?
Zinc metal reacts with hydrochloric acid according to the balanced equation: 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g) When 0.103 g of zinc is combined with enough HCl to make 50.0 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, resulting the temperature of the solution from 22.5oC to 23.7 oC. Find ΔHrxn for this reaction as written. The density, and the specific heat of the solution are 1.00 g/mL and 4.184 J/g...
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 2.65 g of an ore containing 26.0 % Zn(s) by mass? volume: mL
Zinc metal reacts with hydrochloric acid according to the balanced equation: 2HCl (aq) + Zn (s) ® ZnCl2 (aq) + H2 (g) When 0.103 g of zinc is combined with enough HCl to make 50.0 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, resulting the temperature of the solution from 22.5oC to 23.7 oC. Find DHrxn for this reaction as written. The density, and the specific heat of the solution are 1.00 g/mL and 4.184...
Zinc metal reacts with hydrochloric acid according to the following balanced equation. Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When 0.102 g of Zn(s) is combined with enough HCl to make 54.6 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 21.9 ∘C to 24.3 ∘C. Find ΔHrxn for this reaction as written. (Use 1.0 g/mL for the density of the solution and 4.18 J/g⋅∘C as the specific heat capacity