Question

Write the balanced neutralization reaction that occurs between H, SO, and KOH in aqueous solution. Phases are optional. neutralization reaction: Suppose 0.550 L of 0.480 M H,SO, is mixed with 0.500 L of 0.230 M KOH. What concentration of sulfuric acid remains after neutralization? concentration: MH,SO

Answer 1

Reaction: H₂SO_4(aq) + 2 KOH_(aq) $\rightarrow$ K₂SO_4(aq) + 2 H₂O_(l)

Moles of H₂SO₄ = molarity * Volume = 0.48 * 0.55 = 0.264 moles

Moles of KOH = molarity * Volume = 0.23 * 0.5 = 0.115 moles

Moles of H₂SO₄ reacted = 1/2 * moles of KOH = 1/2 * 0.115 = 0.058 moles

Moles reamining = 0.264 - 0.058 = 0.206 moles

Concentration = moles / Volume in liters = 0.206 / 1.05 = 0.196 M