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The balanced equation for the neutralization reaction of aqueous H, SO, with aqueous KOH is shown. H, 50, (aq) + 2 KOH(aq) —
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Answer #1

Kasouly) H₂ Joy (as) takoH Lay) - 2H₂011) + moly of H₂SO4 = 0.290x 14.7 = 4.263 mond to mols of KOH = 2x4.263 & 8.526mme Lon-

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