Question

1) Write the balanced chemical equation for the neutralization reaction of H2SO4 and NaOH
2) why is it necessary to write the balanced chemical equation for the neutralization reaction before calculating the molarity of the unknown solution?
3) How many milliliters of 0.20 M Mg(OH)2 solution are needed to completely neutralize 35.0 mL of 0.15 ?M H3PO4

Answer 1

Y Balancing of a chemical equation make the number of individual octoms same on both sides of the reaction by multiply them with suitable Coefficient Giren Reaction is :- H₂SO4 (al) + NaOH (as) Na₂sou (as) a Mole). 14=3 Naal Na= 2 0 =5 sal H=2 S: 1 0:5 Balanced equation will be :- | H₂SO4 (al) + 2NaOH (ar) > Na, Sou (as) + 2 H₂ol1 85 molarity depends upon the number of displaceable ions. Therefore it is important to balance a neutralisation reaction. As molarity: meles of solute Velleme of soleition (L) so its important to Balance them. Given molarity of mg (OH)2 = 0.2om emi) volumé : ? (vi) (M2) molarity of H₃PO4 = 0.15m. - (V2) Volume = 35m2 ni (mgron)) = 2 as there are two displaceableové na CHapon) a3 as there are 3 displaceable setions. Apply molarity equation: Mivi - M₂ V2 1. Mz ni 0.20% V1 = 0.15835 - 2 volume of mg (on), (",) = 39,4 mL Ans. 5.20 XVI 0.15X35