Question

zation Reactions ( 501 The balanced chemical equation for the reaction of potassium hydroxide with sulfuric acid is H,SO (aq) + 2KOH(aq)-K,SO.(aq) + 2H2O(1) Part Given the balanced neutralization equation from part B, how many moles of potassium hydroxide (KOH) are required to neutralize 2.5 mol of sulfuric acid (H,SO)? Assume that the sulfuric acid completely dissociates in water Express your answer with the appropriate units, either mol or mole. View Available Hint(s) MacBook Pro * One WELRY

Answer 1

The given balanced reaction is

H₂SO_4(aq) + 2KOH_(aq)$\rightarrow$ K₂SO_4(aq) + 2H₂O_(l)

and is completely dissociates in water

from the given reaction we can see that

2 mole of KOH is needed to neutralize 1 mole of H₂SO₄

given moles of H₂SO₄ = 2.5 moles

and from reaction

1 mole H₂SO₄ = 2 mole KOH

hence

2.5 mole of H₂SO₄ = 2.5 mole $\times$ 2 mole of KOH

= 5 mole of KOH

So

5 mole of KOH is required to neutralize 2.5 moles of H₂SO₄