Resources Give The balanced equation for the neutralization reaction of aqueous H.So, with aqueous KOH is...

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Ho soy & 2 Kon - 2 0 (1) + Ko sou mol Hy sou - CXV= 0.140 X (1008) - 1.512 mm mol kon = 2X1512 = 3.024 mmol Vkon = Vkon - mol

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