Question

number 3 and 4 please

2. The Ksp of bismuth iodide, Bil; Molar Mass = 589.68], is 8.1 x 10''. If Bilz (s) is dissolved in pure water, what is the solubility in grams per liter (g/L)? (Suggestion: Write the dissolving equation and Kp expression for Bilz before starting this problem.) a. 3.1 x 10 g/ L b. 7.8 x 10-g/L c. 1.0 x 10-2g/L d. 1.3 x 10-2 g/L e. 1.8 x 10 g/L 3) What is the solubility of Bil; (s) (in g/L) in a solution that contains 0.05 M Biº (aq)? a. 1.5 x 10-'g/L b. 5.0 x 10 g/L c. 3.2 x 1"'Sg/L d. 8.4 x 10 g/L e. 9.6 x 10''g/L 4. What is the solubility (in g/L) of Bil(s) in a solution that contains 0.70 MT (aq)? a. 2.4 x 10-'g/L d. 2.3 x 10-70/L b. 5.2 x 10"" g/L e. 1.4 x 10 g/L c. 6.8 x 10-g/L

Answer 1

3 + Bi Iz (5) - Bila + 3 I (aq) S 35 kop= (Bi3t) [I-J3 = (8) (35) - 2754 8.1x1019-2754 s4= 3x10-20 -5 o s = 1.32 x 10 mollut = 1.32X589,68 xroglur S = 7.8 x10-3 g12 ©

Bi Is (5) - B; 3+ + 3 I Ksp = LBPO [ +)3 8.1X10'- (0.05) (35)3 8.18 10.0.05x2753 $35 162x1013 27 = 6x1019 = 0.84x10-6 mollut = 498 = 0,84x 100 x 589,68 g lur aixo = 4.950 104 ~.5.0*104 g/L 6

Bi 31 T Bi cap) + 3 I lag kpp = [B, 3+] [ I ] 3 \I] = 0.76 14 Ksp = (3) (0.10) sa 8.181019 10.7013 -19 = 23.6 X 10 mol/L = 23.6 X16X589,68 gle = 1.398 10-15 g/L ~ 1.4x1015 g/L ③