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can someone help me answer C?
In an experiment conducted at 74°C, the equilibrium concentrations of reactants and products for the equation shown below wer
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Coc c o + Cl2 Kc [product [ Reactant → Ke - [60] [612] [cocia ke: (1.2 x 102). (0.054) (0.14) Kc = 0.463 x 10-2 Kc = 4.63 x 1Kp = K (RT) - R = 0.0821 atm. L molok T = 74°C = 273 +74) K - 347 K ko = (4.63 x 103) + (0-0821) × (347) Kp = 131.9 x 10-3 Ko

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