Culture site: stitch abscess white, medium sized colony beta hemolysis catalase – positive slide coagulase – positive tube coagulase- positive A disk – negative CAMP test – negative Bile esculin – positive NaCl – positive Optochin disk – negative Bile solubility – negative PYR – negative id the organism
Pus, also known as purulent drainage, is a general term for a collection of thick, often white fluid that accumulates around the source of an infection. This can occur around many types of infections, but can be particularly alarming after surgery.
After a surgical procedure where an incision is made is is possible to have pus coming from the incision if an infection is present. While not all drainage is pus, drainage is often alarming because it can signal the presence of an infection, and can look very strange coming from a surgical incision.
Blood agar is a rich, non-selective medium that supports the growth of most bacteria. However, it is differential based on the ability of the organism to produce enzymes called hemolysins, which lyse red blood cells (RBC). Three patterns of hemolysis can be observed on a blood agar plate.
1. Alpha ( a ) -hemolysis: incomplete lysis of RBC - Greenish, cloudy zone around the colony.
2. Beta ( b)-hemolysis: complete lysis of RBC - A clear zone with a clean edge around the colony.
3. Gamma ( g)-hemolysis: no lysis of RBC - No change in the blood agar around the colony.
MSA contains a high concentration of salt (NaCl), and therefore, selects for the growth of microbes that can tolerate high salt concentrations. Staphylococcus species are halotolerant, whereas Streptococcus species and many other organisms are inhibited by high concentrations of NaCl. MSA also differentiates on the basis of mannitol fermentation. Microorganisms that can ferment mannitol create acidic byproducts, which decrease the pH of the medium and cause the pH indicator, phenol red, to turn yellow.
Expected results:
Staphylococcus aureus
Staphylococcus epidermidis
Streptococcus pneumoniae
Streptococcus pyogenes
The Tube Coagulase Test
Principle:
This method helps to measure free coagulase. The free coagulase secreted by S.aureus reacts with coagulase reacting factor (CRF) in plasma to form a complex, which is thrombin. This converts fibrinogen to fibrin resulting in clotting of plasma.
Procedure:
Applications:
Limitations:
CAMP test was first identified by Christie, Atkins, and Munch-Peterson in 1944 and CAMP test is an acronym of three researchers.
CAMP (Christie, Atkins, and Munch-Peterson) test is used for the presumptive identification of Group B Streptococci (Streptococcus agalactiae). It is the only beta-hemolytic Streptococcus which secrete a protein called CAMP factor or “protein B”. CAMP test rarely give false positive with other Streptococci
Variety of methods are currently available to identify Group B Streptococci (GBS) isolated from clinical specimens. The standard CAMP test and the CAMP spot test (rapid test) are mostly used. Standard camp test are time consuming and/or expensive compared to the CAMP spot test.
Principle
CAMP test detects the production of diffusible, thermostable, extracellular protein known as CAMP factor, produced by Group B Streptococcus. The CAMP factor acts synergistically with the beta lysin produced by Staphylococcus aureus to produce a zone of enhanced lysis of sheep or bovine erythrocytes. The standard CAMP test depend on the elaboration of two toxins during growth to form a typical arrowhead or flame-shaped clearing at the junction of the two organisms when they are placed perpendicular to each other.
The rapid test utilizes an extract of Staphylococcal beta-lysin that acts directly with the CAMP factor previously diffused in the medium around the S. agalactiae colony. A positive CAMP reaction is indicated by an enhanced hemolysis within 30 minutes to 1 hour of adding a drop of CAMP factor reagent
Bile Esculin agar (BEA) is used for this test. BEA is a
selective and differential medium which is presumptively used to
identify Enterococci and group D Streptococci based on the ability
of an organism to hydrolyze esculin. Bile esculin agar contains
oxygall (bile salts, first selective ingredients) to inhibit the
growth of other gram positive organisms other than Enterococci and
group D Streptococci. It contains sodium azide (second selective
ingredients) to inhibit the growth of gram negative organisms. It
also contains nutrients esculin and ferric citrate. Esculin
(differential ingredient) is a fluorescent compound and its
hydrolysis can be observed by a loss of fluorescence.
Bile esculin disk is used for the rapid detection of esculin
hydrolysis in presence of bile for differentiating group D
Streptococci from non-group D Streptococci.
Principle
Bile esculin test is based on the hydrolysis of esculin into glucose and esculetin (6, 7-dihydroxy-coumarin) by a micro-organism that produce an enzyme esculinase. Esculetin reacts with an iron salt (ferric citrate) in the medium to form a phenolic iron complex which produces a dark brown or black color.
Esculin + Acid → β-D-glucose + Esculetin
Esculetin + Fe3+ → Dark Brown Color
Procedure
A. Tube Test
B. Disk Test
Result-
Positive: Blackening of more than half of the
agar slant, if the medium containing ferric ammonium
citrate is used.
NOTE: In case of esculin broth without iron citrate, positive
test means blackening of the broth after addition of the ferric
reagent or by the loss of fluorescence of the medium.
Negative: No blackening of medium.
OR If the agar slant is less than half darkened or medium will fluoresces under UV light.
Positive Disk Test: Development of a dark brown or black color.
Negative Disk Test: Remains colorless
Principle of Bile Solubility Test
Bile or a solution of a bile salt (e.g., sodium desoxycholate) rapidly lyses pneumococcal colonies. Lysis depends on the presence of an intracellular autolytic enzyme, amidase. Bile salts lower the surface tension between the bacterial cell membrane and the medium, thus accelerating the organism’s natural autolytic process.
Procedure of Bile Solubility Test
Limitations of Bile Solubility Test
Enzyme activity may be reduced in old cultures. Therefore, negative results with colonies resembling S. pneumoniae should be further tested for identification with alternate methods.
Result Interpretation of Bile Solubility Test
Positive: Colony disintegrates; an imprint of
the lysed colony may remain in the zone.
Negative: Intact colonies.
PYR (Pyrrolidonyl Aminopeptidase) Test is used for the detection of pyrolidonyl arylamidase (also called pyrrolidonyl aminopeptidase) activity in Streptococcus pyogenes (group A strep), Enterococcus spp., some coagulase-negative staphylococci, and some Enterobacteriaceae. It is also known as PYR (L-pyrrolidonyl-β-naphthylamide) which serve as a substrate for the detection of pyrrolidonyl peptidase.
Facklam, Thacker, Fox and Eriquez reported that 98% of group A streptococci and 96% of group D enterococci hydrolyze PYR. Although Aerococcus species are rarely isolated in the clinical laboratory, these organisms are also expected to hydrolyze PYR.
Facklam et al. further reported that 98% of group B streptococci, 100% of non-group A, B and D streptococci, 100% of group D non-enterococci and 82% of viridans streptococci yield negative PYR test results.
Principle of PYR Test
PYR is a rapid method for presumptive identification of bacteria based on the pyrrolidonyl arylamidase enzyme. The enzyme L-pyrrolidonyl arylamidase hydrolyzes the L-pyrrolidonyl- β-naphthylamide substrate to produce a β-naphthylamine. The β-naphthylamine can be detected in the presence of N,N-methylaminocinnamaldehyde reagent by the production of a bright red precipitate.
Following hydrolysis of the substrate by the peptidase, the resulting b-naphthylamide produces a red color upon the addition of 0.01% cinnamaldehyde reagent. When a visible inoculum of microorganism is rubbed onto a small area of a disk impregnated with the substrate, the hydrolysis occurs within 2 min, at which time the cinnamaldehyde reagent is added to detect the reaction by a color change to purple.
Uses of PYR Test
The Gram Stain
In microbiology, the visualization of bacteria at the microscopic level is facilitated by the use of stains, which react with components present in some cells but not others. This technique is used to classify bacteria as either Gram-positive or Gram-negative depending on their colour following a specific staining procedure originally developed by Hans Christian Gram. Gram-positive bacteria appear dark blue or violet due to the crystal violet stain following the Gram stain procedure; Gram-negative bacteria, which cannot retain the crystal violet stain, appear red or pink due to the counterstain (usually safranin).The reason bacteria are either Gram-positive or Gram-negative is due to the structure of their cell envelope. (The cell envelope is defined as the cell membrane and cell wall plus an outer membrane, if one is present.) Gram-positive bacteria, for example, retain the crystal violet due to the amount of peptidoglycan in the cell wall. It can be said therefore that the Gram-stain procedure separates bacteria into two broad categories based on structural differences in the cell envelope.
Characteristics of Gram-negative Bacteria
Gram-negative bacteria have a characteristic cell envelope structure very different from Gram-positive bacteria. Gram-negative bacteria have a cytoplasmic membrane, a thin peptidoglycan layer, and an outer membrane containing lipopolysaccharide. There is a space between the cytoplasmic membrane and the outer membrane called the periplasmic space or periplasm. The periplasmic space contains the loose network of peptidoglycan chains referred to as the peptidoglycan layer.
Culture site: stitch abscess white, medium sized colony beta hemolysis catalase – positive slide coagulase –...
f. Culture site: stitch abscess White-grey, small sized colony beta hemolytic catalase – -negative coagulase – negative A disk – negative CAMP test – negative Bile esculin – positive NaCl – negative Optochin disk – negative Bile solubility – negative PYR – negative ID: __________
Culture site: wound White to golden, medium sized colony beta hemolytic catalase – positive coagulase latex – positive coagulase tube-negative A disk – negative CAMP test – negative Bile esculin – positive NaCl – positive Optochin disk – negative Bile solubility – negative PYR – positive ID: _____________
Culture site: impetigo white, small sized translucent, colony beta hemolytic catalase – negative coagulase – negative A disk – positive CAMP test – negative Bile esculin – negative NaCl – negative Optochin disk – negative Bile solubility – negative PYR – positive Id this organism
Culture site: Sputum Gram stain: Gram positive diplococci BAP-small, translucent, glistening, umbilicate, alpha-hemolytic CHOC-small, flat, grey, glistening MAC-no growth Catalase-negative Bile Solubility-positive PYR-positive ONPG-negative Urease-negative Optochin-sensitive Mannitol-negative Bile Esculin-negative NaCl-positive Raffinose-positive VP-positive Erythromycin-resistant Clindamycin-sensitive ID:__________________
Question 37 0/1 point A gray-white colony displaying subtle beta-hemolysis is isolated from a cerebrospinal fluid. The organism is a gram-positive rod that is catalase positive, motile at room temperature, and esculin positive. Which patient history is most likely associated with this culture? 2-day-old infant male delivered at 32 weeks gestation 58-year-old cattle farmer 33-year-old female with recent dental surgery 45-year-old female weaver 0/1 point Question 38 A non-motile, VP-positive, gram-negative rod is a possible Shigella species Enterobacter species. Klebsiella...
Question 6 2 points Sre Answer A patient is hospitalized for endocarditis. Multiple blood cultures grow out a catalase negative, alpha hemolytic gram positive coccus. The clinical history of the patent reveals that the patient had recently had extensive dental surgery performed. Which of the following organisms is Most Like the solated organism O A) Staphylococcus aureus O B) Streptococcus ogalactice O ) Viridans Streptococcus O D) Streptococcus gallolyticus OE) Enterococcus foecium Question 8 Which of the following is NOT...