Answer:-
From the given data it is evident that on increasing the concentration of A , there is no change in the rate. So rate expression is independent of concentration of A but on doubling the concentration of B , rate become solved four time, the rate of reaction with respect to B is second order but in case of C on increasing the concentration of to 2.5 time , rate becomes 2.5 times of initial acid.
So rate expression is given as follows,
d. k[B]2[C]
need help with #3 please QUESTION 3 Determine the rate-law expression for the reaction below at...
a. Given these data for the reaction A + B → C, write the rate-law expression. Use k for the rate constant.) b. What is the value, with units, for the specific rate constant? The specific rate constant- Initial Rate of Initial [A] Initial [B] Formation of C Expt. (M) (M.s-1) 0.30 0.30 0.60 0.20 0.40 0.80 4.0 x 10-5 1.6 x 10-4 2.6 x 10-3
Given the initial rate data for the reaction A+BC, determine the rate expression for the reaction. [A], M [B].M Initial rate, M/S 0.10 0.20 5.00 10.20 0.20 10.0 0.10 0.15 2.81 O rate=250[A][B] rate - 5.0[A][B] rate=250[A)? rate - 50.0[A] rate= 1250[A][B] The first-order reaction A --> B+C has a half-life of 3.00 minutes. The rate equation for this reaction is rate = 1.50 min-1[A] rate = 1.05 min [A] O rate = 4.34 min [A] rate = 0.405 min...
Given the data, determine the rate law expression for the reaction: 2A+B(2 subscript)+C --> A(2 subscript)B+BC 3Given the dts taulated elow, determine the rate-law expression for the reactio Insitial Rate of Formation of C of BC Thal Ruia Deoitial ( itialIC 0.20 M 40M 0.20 M 0.20 M 0.20 M 0.30 M 0.30 M 040 M 0.20 M 020 M 0.20 M 0 60 M 24 x 10* M/min 96 x 10 M/min 24 x 10 M/min 72 x 10"...
1. Shown below are the results of four separate experiments measuring reaction rate for the following reaction: 2 A+3B+C - 2D+3E Trial [A. BL. C. Initial rate (M/s) 0.01 0.20 0.10 1.67 x 10+ 2 0.02 0.20 0.20 1.33 x 10-3 3 0.02 0.20 0.10 3.33 x 104 4 0.01 0.40 0.10 1.67 x 10-4 c. What is the rate when the initial concentrations for all reactants is 0.15 M?
1) Determine the rate law and the rate constant given the data below. 2 MnO4 (aq) + 5 C103(aq) + 6 H+(ag) Experiment Mn04] 0.10 2 0.25 3 0.10 4 0.10 2 Mn2+ (aq) + 5 C104 (aq) + 3 H20 (1) [C103] [H] Initial Rate(M/s) 0.10 0.10 5.2 x 10-3 0.10 0.10 3.3 x 10-2 0.30 0.10 1.6 x 10-2 0.10 0.20 7.4 x 10-3
1. TL .lowing te deta was obtained experimentally. Rxn: A +28. 3 . D Rate (M/S) (M) [B] (M) C (M) 2.0 2056 0.050 0.20 2.0 0.050 0.10 0.20 50 0.25 0.10 0.20 16 0.050 0.40 a. Determine the rate law expression for this reaction (15 pts). Rate 4 = 0.40 = K [65[o oboJo no 2 - 8 Rate 2 0 .20 2 K[2[650[ 10 0.10 'b. What is the value for the rate constant (with proper units) (5...
Class Practice C152-02 Chapter 16 Practice 2 - Rate Law Consider a chemical reaction between compounds A and B that is first order with respect to A, first order with respect to B. and second order overall. From the information given below, fill in the blanks Initial Rate Initial (A) Initial [B] Experiment (Mrs) (M) (M) 1 4.0 x 100 .20 0.050 2 1 .6 x 102 0.050 3 3.28 10² 0.40 T Consider the following rate data for the...
1. Initial rate data at 25.0 °C are listed below for the reaction: 2 HgCl2 (aq) + C,042 (aq) → 2 (aq) + 2 CO2(g) + HgCl(s) Expt. [HgCl2]0 [C:02) Initial rate/Ms? 0.100 0.20 0.100 0.40 3.1 x 105 1.2 x 104 6.2 x 10-5 0.050 0.40 Use the data to determine the rate law for the reaction. 2. At 500 °C, cyclopropane (C3H.) rearranges to propene (CH:CH-CH2): CH. (g) → CH,CH=CH2 (8) The reaction is first order and the...
1. Initial rate data at 25.0 °C are listed below for the reaction: 2 HgCl2 (aq) C2O (aq)2 C (aq)+ 2 CO:(g)+ Hg Cl(s) (COP)0 Expt. HgClalo Initial rate/ 3.1 x 10 1 0.100 0.20 1.2x 10 0.100 0.40 6.2x 10S 0.050 0.40 Use the data to determine the rate law for the reaction. 2. At 500 °C, cyclopropane (CsH6) rearranges to propene (CH3CH-CH2): CH CH=CH2 (g) CaHs (g) The reaction is first order and the rate constant is 6.7...
Using the following data, determine the rate law and calculate k: rate = k[F2]x[ClO2]y Experiment [F2] (M) [ClO2] (M) Initial rate (M/s) 1 0.40 0.05 1.2 M/s 2 0.20 0.10 0.60 M/s 3 0.40 0.10 2.4 M/s