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C 5.50 ml of a (n) 9.50 MKOH solution diluted to 75.0 ml
Problem 9.108 - Enhanced -with Feedback You may want to reference (Pages 306-308) Section 9.5 while completing this problem P
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part AS My = Ma Ye m, = Initial = Initial Hel molarity = 11.2 Hol volume = 55 m2 V = final molarily = x a final volume = S245part B: Weight = - miut 1000 100 Molarities of 236 Nhy Cl 23 23 x 1000 3 · 53.491 100 (4.2998 m] 98 M then miv, = M₂ V₂ m =.4WW 1 Partei- m., = Mive . M, = 9.50 m ; : 5.50 mL m₂ = x V₂ = 75 mL . . = 9.50 X5.50 = xx 75 = 10.6967MB

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