![consumers, xit A&B be two apples a brocolli & b. Endowmcuts UAl AA , BA) = 2aA +56 A. UB (ab, bB) = abbo. (812) (278) brocoll](//img.homeworklib.com/questions/6fb512f0-7886-11ea-9612-35ebb330e6ed.png?x-oss-process=image/resize,w_560)
![Date B DELTA PO NO 100 8 10 Any allocation inside ne avea enclosed by ICA & ICB is have to superior to w as alleast I individ](//img.homeworklib.com/questions/7069f2b0-7886-11ea-b4aa-1bfb2702aea0.png?x-oss-process=image/resize,w_560)
![c is rence .. pareto superior to X cant be PE. OA OB are pe ie . the points on contract curve there is no p.S allocation to m](//img.homeworklib.com/questions/711d0d00-7886-11ea-a272-63b374461de1.png?x-oss-process=image/resize,w_560)
![DELTA Pg No Competitie egy CLE): Marsheliau demands For A u= 204 + sba be a baş CA, bon od Milo Poc 7 Pa 22 Po 5 of Mo if a L](//img.homeworklib.com/questions/71ded6d0-7886-11ea-90bc-eb8cf2212537.png?x-oss-process=image/resize,w_560)
![For CE , he markets must clear it - QAtaB = w êt war = 10 ba+bos = W6A + ? = 10. checking for market clearance assume price v](//img.homeworklib.com/questions/72a2d7d0-7886-11ea-a450-8968af50800f.png?x-oss-process=image/resize,w_560)
![at P7215 aAtaB =10 ot M2 =10 2P = 2P+8 =10 2P = 180=8 P = 419.7215 . competitive price is P44/9,1) Pa=4 Pb=9 . or](//img.homeworklib.com/questions/735b34e0-7886-11ea-829c-9f741fc9f996.png?x-oss-process=image/resize,w_560)
![For A. Alw cations: MI 8P+2 AA=0 bA= 22 864/9)+2 = 3270 2 18 = 2.8. = for Bi AB= M2=2P+8 - 2P 2P = 2(4/9)+8 21419) 8 +72 8 =](//img.homeworklib.com/questions/73fa9910-7886-11ea-8c7f-a3fe1d36a9a6.png?x-oss-process=image/resize,w_560)
consumers, xit A&B be two apples a brocolli & b. Endowmcuts UAl AA , BA) = 2aA +56 A. UB (ab, bB) = abbo. (812) (278) brocolli the black wies are Ic of A which are with slope 2/s. The green curues are Inicial endowment is Pauit w a { (812); (2,8) } . substitutes IC of B Any allocation on the It passing via w l for Pareto superius allocation is an allocation where - no body is worse off a atleast one indiuidug strictly better off s es pareto superior to s' il ai (s)>, uils) #set tien ails) > uics I for alleast onese CEN
Date B DELTA PO NO 100 8 10 Any allocation inside ne avea enclosed by ICA & ICB is have to superior to w as alleast I individuel is strictly better off & no one is worse off. 6 Pareto effiuent allocation is one where you cannuot find a pareto silperior allocation & it must be feasible. lo The fet points A,B,C all are PE and There is no pareto superior allocation to these point - here & MRSA = MRS B - the two ICs are tangent to each other. (1 to check if they are PE Take any other point x a to show it is not parreto efficient! If we move from X to c the IC of B is same so it is has the same utility but Iho we are on a higher IC for A. Hence A is strictly better off while B is no worse off
c is rence .. pareto superior to X cant be PE. OA OB are pe ie . the points on contract curve there is no p.S allocation to mese. Mathematically & the set of points where MRSA=MRSB. are PE 2= bb 5 AB. Lag=5bbl contract 2 1 10-2A) = 5 (10-ba) 20-204 = 5o- sba 15bA - 2a4 = 301 curre
DELTA Pg No Competitie egy CLE): Marsheliau demands For A u= 204 + sba be a baş CA, bon od Milo Poc 7 Pa 22 Po 5 of Mo if a L 23 C. if a 2/5 аа | Раа. + Pb bл 4 м, у ра – 2/s Т 6 For B: UB= abbo. at eg in Slope of IC = slope of BL (you can also use MRS = palpb. At in Kang rangean) bB = Pa a) bB = ab Pa AB + Pb. A Pb ,- Puttup it in B.L. S pa. AB + Pbl abba l-M2 AB - M2 , bB = M2 altls/ alati 2Pb.
For CE , he markets must clear it - QAtaB = w êt war = 10 ba+bos = W6A + ? = 10. checking for market clearance assume price vector - PE [Pi] as we take bas numeraine. li) of P( relative price) L215 se men antaB=10. en Mit M2 =10 o per 2Pa Mi = pawåt Pb WGA = 8pa +2. M2 = pa waB +PG w 3 =28a+8. LHS) Now, 2(8 pest2) + 2Pet8 apa lopaty +220 +8 2le - 12 Pa + 12 = - 2P 6 Perb pe Rhs 10 - - 6Path = 10 - upe = 6 Pa- 3/2 Pa is not un han 2/5 not possible-
at P7215 aAtaB =10 ot M2 =10 2P = 2P+8 =10 2P = 180=8 P = 419.7215 . competitive price is P44/9,1) Pa=4 Pb=9 . or
For A. Alw cations: MI 8P+2 AA=0 bA= 22 864/9)+2 = 3270 2 18 = 2.8. = for Bi AB= M2=2P+8 - 2P 2P = 2(4/9)+8 21419) 8 +72 8 = 10 do = M2 = 214/9+8 = 8 +72 a 2 = 4.44 18 Hence : allocati ens : Ş (012:8), 610, 4.44)' to check PE see if it satisfies contract warue equ 5ba- 2aA=30 5(2.8) -0 =30 NO (PH It is not in the sentract connue ACE is not PET