Question

The oxidation of copper(I)oxide, Cu,O(s), to copper(II)oxide, CuO(s), is an exothermic process. 2 Cu,0(s) + O2(g) — 4 CuO(s)

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Answer #1

Molar mass of Cu2O,

MM = 2*MM(Cu) + 1*MM(O)

= 2*63.55 + 1*16.0

= 143.1 g/mol

mass(Cu2O)= 34.36 g

use:

number of mol of Cu2O,

n = mass of Cu2O/molar mass of Cu2O

=(34.36 g)/(1.431*10^2 g/mol)

= 0.2401 mol

Since Δ H is negative, heat is released

when 2 mol of Cu2O reacts, heat released = 292.0 KJ

So,

for 0.2401 mol of Cu2O, heat released = 0.2401*292.0/2 KJ

= 35.06 KJ

Answer: 35.1 KJ

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