Question

7. If H,PO, has K, -6.83 x 10, and Hco, has K,-5.8x 10", which is the weaker acid? Circle your answer and explain how you know. (Ipt 8. For a solution with pH 9.74, calculate the following: (3pa) [H'] [OH] pOH- 9. (2pas total) a. A solution of a weak acid with concentration 0.11 M. is 8.8 % ionized. Calculate its K, value. K, b. Calculate the K, value of a 0.060 M solution of a monoprotic acid with [H'] -2.7 x 10 M.

Answer 1

6 Given that Hapoy has ka=6.83 x 108 Hacon has kaa 5-8 x 1010 we know that Ka is acid dissociation constant if value of acid dissociation constant is higher than acid will be strong acid and complete dissociation of acid will take place lesser value of Kalacid dissociation constant indicate that arid is Weak and acid will not dissociate completely. since. Ka value of H₂PO4 ie. 6.83x10 is higher than ka value of Hacon i so Hapo4 will be stronger acid than Hacogi Hence, H2CO3 will be weaker acid, bcoz of lower Ka value than H2PO4 Answer - H₂ C3 weaker acid 6 Given that pH=9.74 I we know that pH = -log[ut] so - Log [Ht] =9.74 Log I H+] = -9.74 [H+] = 109.74 so. [ht] = 1.82x1010 Hence, [ut] =11.82x10-10

we know that рн +рон — 14 Sо, рен – 4 = PH since, PH laiven) 9.74 рен — 14-рн — 14 – 9.4 - 4:26 Hence, ров — : 2 | we know that pot - - Logo [ok]. Se, — Lo3 «Сон) — 4:16 Lo91Lон 1 — Ч. 2 с Сон 2 - 14:26 - 549x16s Hence a Сен 1 - 1 s. 49 x16 57 Answers [H+] = 1.82x1010 Сон 1 - 5.49x to ѕ Рон — Ч.