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3.2.3 Suppose that a disease is inherited via a sex-linked mode of inheritance, so that a male offspring has a 50% chance of inheriting the disease, but a female offspring has no chance of inheriting the disease. Further suppose that 51.3% of births are male. What is the probability that a randomly chosen child will be affected by the disease?
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Answer #1

Now,

The probability that a randomly chosen child will be affected by the disease

= P(child will be affected by the disease and child is male) + P(child will be affected by the disease and child is female)

= P(child will be affected by the disease | child is male)*P(child is male) + P(child will be affected by the disease | child is female)*P(child is female)

= (0.5*0.513) + (0*(1-0.513))

= (0.5*0.513)

= 0.2565

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