A= d[(1+i)^n-1]/i
A= 60000
i= 0.07
n= 8
60000= d[(1+0.07)^8 - 1]/0.07
4200= 0.718186*d
d= 5848.067
Annual amount deposited should be 5848.067 per year.
Problem 2.3 Uniform savings for a future investment Given: You wish to have $60,000 to invest...
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